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• Количество слайдов: 9 N 1 -4 Linear Application Problems OBJECTIVE: Student should be able to… ØIdentify and describe a variable and expression ØEvaluate an expression ØSolve an equation Objective 2: Demonstrates an understanding of the properties and attributes of functions. Objective 4: Formulates and uses linear equations and inequalities. As soon as you sit down work on WARM UP # 4 (you will only have approx. 3 minutes. NO TALKING!! TAKS WARM UP #2 Objective 4: Formulates and uses linear equations and inequalities. 9. Auto-Check Motors charged Mr. Jones \$84. 00 for an automotive part plus \$68. 00 per hour that a mechanic worked to install the part. The total charge was \$353. 00. For about how long did the mechanic work to install the part on Mr. Jones’s car? A. 6 h B. 5 h 68. 00 x + 84. 00 = 353. 00 - 84. 00 -84. 00 C. 4 h _______ 68. 00 x = 269. 00 68. 00 D. 3 h x = 3. 96 TAKS WARM UP #2 Objective 4: Formulates and uses linear equations and inequalities. 10. Ms. Kitts works at a music store. Last week she sold 6 more than 3 times the number of CDs that she sold this week. Ms. Kitts sold a total of 108 CDs over the 2 weeks. Which system of equations can be used to find l, the number of CDs she sold last week, and t, the number of CDs she sold this week? l = last week F. l + t = 108 t = 3 l + 6 G. l + t = 108 t = 3 l − 6 H. l + t = 108 l = 3 t − 6 J. l + t = 108 l = 3 t + 6 t = this week l = 3 t + 6 l + t = 180 N 1 -4 Linear Application Problems Write an equation for each of the following and solve. Round answers appropriately. 1. At the end of the day, Jeff found that the total cash register receipts at the motel where he works were \$286. 20. This included sales tax of 8%. Find the amount of the tax. Total = Cost + Tax 286. 20 = x +. 08 x ____ 286. 20 = 1. 08 x ___ 1. 08 265 = x (amount before the tax) Tax =. 08(265) Tax = \$21. 20 or 286. 20 - 265 N 1 -4 Linear Application Problems Write an equation for each of the following and solve. Round answers appropriately. 2. Louise got scores 88 and 78 on her first two tests. What score must she make on her third test to keep an average of 80 or greater? (3) 88 + 78 + x > 240 166 + x > 240 -166 x > 74 Must make 74 or better on the 3 rd test. N 1 -4 Linear Application Problems Write an equation for each of the following and solve. Round answers appropriately. 3. A couple wishes to rent a car for one day while on vacation. Ford Car Rental wants \$15 per day and \$0. 14 per mile, while Chevrolet-For-A-Day wants \$14 per day and \$0. 16 per mile. After how many miles would the price to rent the Chevrolet exceed the price to rent the Ford? Chevrolet > Ford 14 +. 16 m > 15 +. 14 m -14. 16 m > 1 +. 14 m -. 14 m. 02 m ____. 02 >1 ___. 02 m > 50 After 50 miles. N 1 -4 Linear Application Problems Write an equation for each of the following and solve. Round answers appropriately. 4. Steve is saving to buy a car. He has decided he will start looking as soon as he has saved \$2000. If he has \$1100 in savings now and he can save \$150 a month, how many months will it be before Steve can begin looking at cars? x = # months 1100 + 150 x = 2000 -1100 150 x ____ = 900 150 x=6 150 6 months N 1 -4 Linear Application Problems Write an equation for each of the following and solve. Round answers appropriately. 5. Ledd Corporation produces a CD-RW drive at a cost of \$120 each with fixed costs of \$36, 000. The CD-RW drive sells for \$180. How many drives must Ledd Corporation sell to break even? d = # drives cost = sales 120 d + 36000 = 180 d -120 d _____ 36000 = 60 d 60 60 600 = d 600 drives N 1 -4 Linear Application Problems Write an equation for each of the following and solve. Round answers appropriately. 6. A publishing company finds that the cost of publishing a certain book is \$12. 50 per copy. The fixed costs for publishing the book are \$35, 000. How many books must the company publish and sell in order to have a profit of at least \$15, 000 if each book sells for \$25? b = # books money sales – cost > profit 25 b – (12. 50 b + 35000) > 15000 4000 books or more 25 b – 12. 50 b - 35000 > 15000 12. 50 b > 50000 12. 50 b - 35000 > 15000 b > 4000 + 35000 +35000 