Lecture 3 Demand for junctions Domestic Demand

Lecture 3 Demand for junctions

Domestic Demand: Domestic J# Elevatio ( n ( m Area Q Density Population ( m² ) ( m 3/d ) J 1 34. 03 3256. 82 0. 05 162. 84 32. 98 J 2 29. 06 6493. 58 0. 05 324. 68 65. 75 J 3 25. 30 5778. 82 0. 05 288. 94 58. 51 J 4 25. 20 6637. 21 0. 05 331. 86 67. 20 J 5 26. 70 4675. 62 0. 05 233. 78 47. 34

Domestic Demand: For the 1 st junction : P domestic = Area*Population Density = 3256. 82* 0. 05= 163 Q domestic = P domestic*150 *1. 35 /1000 = 32. 98 m³/d Average Demand for capita / day =150 L/c/d The value 1. 35 = 25% loses in the network and the equivalent commercial demand which was taken 10% domestic demand.

Public Demand: For public demand: Average Demand for capita / day = 40 L/c/d Q public = # employee * 40 * 1. 25 (25% UFW)

Public Demand: Public J# Area Employees # ( m² ) Q ( m 3/d ) J 1 0 0 0 J 2 0 0 0 J 3 0 0 0 J 4 548. 38 109. 68 5. 5 J 5 1922. 40 384. 48 19

Public Demand: For junction 4 which has a public demand, Area = 548. 38 m² , Let # of employee = 0. 2*Area =109. 68 =110 person Q public =110*40*1. 25/1000 = 5. 5 m³ /day

Commercial Demand: For junction which has a commercial demand, Let # of = 1200 person/day Average Demand for capita / day = 30 L/c/d Q Commercial = 1200*30*1. 25/1000 = 45 m³ /day (25% UFW)

Industrial Demand: For junction which has an industrial demand, Let # of workers = 850 person Average Demand for capita / day = 30 L/c/d Add 30% for cleaning works. . etc Q Industrial = 850*30*1. 55/1000 = 40 m³ /day (25% UFW, 30% Others)

School Demand: For junction which has a school demand, # of pupils/school = 1200 pupil Average Demand for capita / day = 10 L/c/d Q school = 1200*10*1. 25/1000 = 15 m³ /day (25% UFW)

Hospital Demand: For junction which has a hospital demand, Let # of beds = 160 Average Demand for capita / day = 300 L/c/d Q Hospital = 160*300*1. 25/1000 = 60 m³ /day (25% UFW)

Mosque Demand: For junction which has a mosque demand, # of prayers/day =500 person Average Demand for capita / day = 25 L/c/d Q Mosque = 500*25*1. 25/1000 = 15. 7 m³ /day (25% UFW)

Agricultural Demand: For junction which has a agricultural demand, Agricultural demand varies according to the type of trees. Demand for Green areas = 5 m 3/Donum/Week Average Demand / day = ? ? ? m 3/d Don’t Forget (25% UFW)

Tourist Demand: For junction which has a tourist demand, Demand for Hotels = 180 L/C/d Average Demand / day = ? ? ? m 3/d Don’t Forget (25% UFW)

Total Demand: Qtotal of network = ∑ Qnodes m 3/day Average Demand: For each type of demand Qavg_i = ∑ Qnodes / 24 m 3/hr Where (i) is the type of demand

Example. . Qtotal of network (m 3/day)

Questions