Скачать презентацию Evaluate the numerator and the denominator separately Multiply Скачать презентацию Evaluate the numerator and the denominator separately Multiply

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Evaluate the numerator and the denominator separately. Multiply 40 by – 2. Simplify the Evaluate the numerator and the denominator separately. Multiply 40 by – 2. Simplify the numerator and the denominator. Then divide.

The Additive Inverse Property says that a number plus its opposite is 0. The Additive Inverse Property says that a number plus its opposite is 0.

Since – 7 + 7 = 0, the additive inverse of – 7 is Since – 7 + 7 = 0, the additive inverse of – 7 is 7.

Original equation Simplify. Original equation Simplify.

Simplify. Simplify.

Area of a trapezoid Multiply each side by 2. Simplify. Area of a trapezoid Multiply each side by 2. Simplify.

Original equation Subtract 7 from each side. Original equation Subtract 7 from each side.

Subtract 250 from each side. Simplify. Divide each side by 5. Simplify. Subtract 250 from each side. Simplify. Divide each side by 5. Simplify.

Simplify 2(4) first. Subtract 8 from 6. Add. Simplify 2(4) first. Subtract 8 from 6. Add.

|5 + 3| = 8 |– 11 + 3| = 8 |8| = 8 |5 + 3| = 8 |– 11 + 3| = 8 |8| = 8 |– 8| = 8 8=8

A circle means that this point is not included in the solution set. A circle means that this point is not included in the solution set.

Original inequality Divide each side by – 0. 3, reversing the inequality symbol. Simplify. Original inequality Divide each side by – 0. 3, reversing the inequality symbol. Simplify.

A dot means that this point is included in the solution set. A dot means that this point is included in the solution set.

Original inequality Multiply each side by 2. Divide each side by – 3, reversing Original inequality Multiply each side by 2. Divide each side by – 3, reversing the inequality symbol.

Original inequality Subtract 1. 59 from each side. Simplify. Divide each side by 2. Original inequality Subtract 1. 59 from each side. Simplify. Divide each side by 2. 89. Simplify.

Graph the solution set for each inequality and find their intersection. Graph the solution set for each inequality and find their intersection.

Solve each inequality separately. or Solve each inequality separately. or

All of the numbers between – 3 and 3 are less than 3 units All of the numbers between – 3 and 3 are less than 3 units from 0.

The rent for an apartment can differ from the average by as much as The rent for an apartment can differ from the average by as much as $250.

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