11 2 Triangles and Parallelograms T 100

11. 2 Triangles and Parallelograms

T 100: The area of a parallelogram is equal to the product of the base and the height. A = bh h b M A 13 cm Find the area of 6 cm H 9 cm T MATH

Why is the Area = bh?

M A 13 cm 6 cm H 9 cm T A = bh = 13(6) = 78 cm 2 You will receive one point for each line, plus the correct unit. Minimum 3 lines.

T 101: The area of a triangle is equal to one-half the product of a base and the height (or altitude) for that base. A = bh h b Where b is the length of the base and h is the altitude. Altitude may be inside, outside or the leg of the triangle. The base may not always be at the bottom.

12 mm 8 mm 15 x Find the area of this triangle. Find the base of a triangle with an altitude of 15 and area 60.

15 x Find the base of a triangle with an altitude of 15 and area 60.

Find the area of a parallelogram whose sides are 14 and 6 and whose acute angle is 60˚. Draw and label. D 14 U 6 60˚ K C How will you find the height?

D 14 U 6 60˚ K C S Drop line DS to form a 30 -60 -90 triangle. Line DS is A = bh = 14( = 42 )

The diagonals of a kite are 10 and 24. Find the kite’s area. Draw the shape, label. What shapes do you have to use? Write the formula needed and solve.

Assignment: Make your own area problem! Come up with creative picture (ex: fish, bird, house) that involves at least 4 different shapes (circles, rectangles, parallelograms, triangles). Write a rough draft and then a final draft on the construction paper. Leave room on your final draft for someone to solve your problem. You have 15 minutes to come up with the problem When finished: Pass your problem to the person behind you to calculate the area!

Get the homework done so you don’t have any over the break! Pg 519 #2 -20 Evens