Скачать презентацию 0 016 3 0 048 0 0091 Скачать презентацию 0 016 3 0 048 0 0091

255e24c08876e69b6065534aab99eab4.ppt

  • Количество слайдов: 193

0. 016 3 0. 048 0. 016 3 0. 048

0. 0091 5 0. 0455 0. 0091 5 0. 0455

8. 3 2. 9 747 + 166 24. 07 8. 3 2. 9 747 + 166 24. 07

0. 12 5. 3 36 + 60 0. 636 0. 12 5. 3 36 + 60 0. 636

0. 029 1. 8 232 + 29 0. 0522 0. 029 1. 8 232 + 29 0. 0522

$14. 60 15. 75 7300 10220 7300 + 1460 229. 9500 $14. 60 15. 75 7300 10220 7300 + 1460 229. 9500

Estimate to find the weight of each whale in pounds and then subtract to Estimate to find the weight of each whale in pounds and then subtract to find a reasonable estimate of the difference.

Blue whale: 2, 000 × 151 2, 000 300, 000 – 80, 000 = Blue whale: 2, 000 × 151 2, 000 300, 000 – 80, 000 = 220, 000 Humpback whale: 2, 000 × 38. 1 80, 000

Look back at the problem. A blue whale weighs about 150 – 40 or Look back at the problem. A blue whale weighs about 150 – 40 or 110 more tons than a humpback whale. This is equal to 110 × 2, 000 or 220, 000 pounds. So the answer is reasonable.

2. 4 3 7. 2 – 6 12 – 1 2 0 2. 4 3 7. 2 – 6 12 – 1 2 0

0. 44 15 6. 60 – 0 66 – 6 0 60 – 60 0. 44 15 6. 60 – 0 66 – 6 0 60 – 60 0

First, add all the data together. 6. 22 6. 00 6. 11 + 6. First, add all the data together. 6. 22 6. 00 6. 11 + 6. 11 24. 44 Divide by the number of addends to find the mean mass. 6. 11 4 24. 44

6. 4 21. 44 3. 34 64 214. 40 – 192 22 4 – 6. 4 21. 44 3. 34 64 214. 40 – 192 22 4 – 19 2 3 20 – 3 20 0

21. 44 divided by 6. 4 is 3. 34 × 6. 4 = 21. 21. 44 divided by 6. 4 is 3. 34 × 6. 4 = 21. 44

0. 4 72. 0 180. 4 720. – 4 32 – 32 00 – 0. 4 72. 0 180. 4 720. – 4 32 – 32 00 – 0 0

2. 4 0. 024 0. 01 24 0. 24 – 0 02 – 0 2. 4 0. 024 0. 01 24 0. 24 – 0 02 – 0 24 – 24 0

42. 88 786. 85 42. 88 786. 85

18. 35 42. 88 78685. 00 – 4288 35805 – 34304 1501 0 – 18. 35 42. 88 78685. 00 – 4288 35805 – 34304 1501 0 – 1286 4 2146 0 – 2144 0 20

Make an organized list to see the different possibilities and use estimation to be Make an organized list to see the different possibilities and use estimation to be sure he spends about $15.

Check the list to be sure that all of the possible combinations of sporting Check the list to be sure that all of the possible combinations of sporting good items that total no more than $15 are included.

1 5 Find a multiple of 5 that is close to 16. 1 5 1 5 Find a multiple of 5 that is close to 16. 1 5 1 5

1 4 Find a multiple of 4 that is close to 23. 1 4 1 4 Find a multiple of 4 that is close to 23. 1 4 1 4

1 4 3 4 1 4 3 4

4 5 1 6 1 6 = 1 6 4 5 1 6 4 5 1 6 1 6 = 1 6 4 5 1 6

Round each mixed number to the nearest whole number. Round each mixed number to the nearest whole number.

6 7 8 2 1 4 6 7 8 2 1 4

1 5 1 6 = 1× 1 5× 6 = 1 30 1 5 1 6 = 1× 1 5× 6 = 1 30

1 2 5 8 = 5 8 1 2 7 1 5× 7 = 1 2 5 8 = 5 8 1 2 7 1 5× 7 = 8× 1 = 35 3 or 4 8 8

3 8 1 2 3 8 1 2

1 2 3 7 3× 2 2 = 9 7× 9 6 2 = 1 2 3 7 3× 2 2 = 9 7× 9 6 2 = or 63 21

2 21 2 21

3 4 = 2 3 3× 2 4× 3 1 = 2 3 4 3 4 = 2 3 3× 2 4× 3 1 = 2 3 4 2 3 1 2

1 2 3 8 1 3 = 3 8 10 3 = 3 × 1 2 3 8 1 3 = 3 8 10 3 = 3 × 10 8× 3 = 5 or 1 1 4 4 1 3 10 3 1 2

1 5 1 2 1 5 1 2

1 5 1 21 = 2 5 3 2 = 21 × 3 5× 1 5 1 21 = 2 5 3 2 = 21 × 3 5× 2 = 63 or 6 3 10 10 3 10

4 5 3 4 = 15 4 14 5 = 21 or 10 1 4 5 3 4 = 15 4 14 5 = 21 or 10 1 2 2

Since, 8 × 1 1 = 1, the reciprocal of 8 is. 8 8 Since, 8 × 1 1 = 1, the reciprocal of 8 is. 8 8 1 8

Since, 5 5 3 3 × = 1, the reciprocal of is. 3 3 Since, 5 5 3 3 × = 1, the reciprocal of is. 3 3 5 5 5 3

1 3 5 1 = 6 3 = 1× 6 3× 5 = 2 1 3 5 1 = 6 3 = 1× 6 3× 5 = 2 5 6 5

1 5 = 6 1 30 or 30 = 1 1 5 = 6 1 30 or 30 = 1

Divide 3 into 4 equal parts. 4 Divide 3 into 4 equal parts. 4

3 4 1 4 3 = 4 1 4 = = 3 16 3 4 1 4 3 = 4 1 4 = = 3 16

1 4 1 25 = 2 4 5 2 25 4 2 5 = 1 4 1 25 = 2 4 5 2 25 4 2 5 =

= 25 4 2 5 = 5 or 2 1 2 2 = 25 4 2 5 = 5 or 2 1 2 2

5 8 2 3 = 21 8 3 2 = 63 or 3 15 5 8 2 3 = 21 8 3 2 = 63 or 3 15 16 16 = 2

3 4 = 180 1 15 4 3 4 = 180 1 15 4

= 180 1 = 720 15 = 48 4 15 = 180 1 = 720 15 = 48 4 15

Five-Minute Checks Five-Minute Checks