Volumes of Revolution Consider the line y=3

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Volumes of Revolution Volumes of Revolution

Consider the line y=3 x • Now rotate the line 360° about the x axis. AsConsider the line y=3 x • Now rotate the line 360° about the x axis. As you can see the result is a solid cone. The volume of the cone can be thought of as a series of discs or cylinders.

Volume of a cylinder • The volume of a cylinder is the area of the circularVolume of a cylinder • The volume of a cylinder is the area of the circular cross-section multiplied by the height. • The area of a circle is π r 2 • The height is h • So V= π r 2 h • We can think of a disc as a very thin cylinder

Consider a small disc in the cone • The volume of the disc is the areaConsider a small disc in the cone • The volume of the disc is the area of the circular cross-section multiplied by the height (or length in our case). • Now the radius of the circular cross-section is y and the length of the disc is δ x. • So V= π y 2 δ x

Integration as a process of summation • We have seen that integration is a process ofIntegration as a process of summation • We have seen that integration is a process of summation that adds a series of very small strips to give an area. • This process can also be used to add a series of very small discs. • As with areas, as δ x→ 0, the limit of the sum gives the result that the volume of revolution about the x axis is given by dxydxy

Volumes of revolution example • As with area, vertical boundaries can be added in the formVolumes of revolution example • As with area, vertical boundaries can be added in the form of limits:

General formula • So the Volume of Revolution between the limits of x=a and x=b aboutGeneral formula • So the Volume of Revolution between the limits of x=a and x=b about the x axis can be found with • Similarly, the Volume of Revolution between the limits of y=a and y=b about the y axis can be found with b a dxy 2 b a dyx 2 a b

Example 1 • Find the volume generated when the area defined by the following inequality isExample 1 • Find the volume generated when the area defined by the following inequality is rotated completely about the x axis: )4(0 xxy

Example 1 Solution • So our four boundary equations are:  • x-axis • curve •Example 1 Solution • So our four boundary equations are: • x-axis • curve • x-axis intercept 4 0 x x xxy y

Example 1 Solution • Hence the volume of revolution is: 15 512 3 416 42 5Example 1 Solution • Hence the volume of revolution is: 15 512 3 416 42 5 4 3 16 2 5 168)4( 3 4 5 4 0 234 4 0 22 x x x dxxxxdxxx

Example 2 • Find the volume generated when the area defined by the following inequalities isExample 2 • Find the volume generated when the area defined by the following inequalities is rotated completely about the y axis: 2 , 0 , 1 2 y x xy

Example 2 Solution • So our four boundary equations are:  • y-axis • curve •Example 2 Solution • So our four boundary equations are: • y-axis • curve • y-axis intercept • line • Since we are integrating wrt y we need the equation of the curve in terms of x 2. 2 1 1 0 2 y y xy x

Example 2 Solution • So,  • Hence the volume of revolution is:  2 1Example 2 Solution • So, • Hence the volume of revolution is: 2 1 1 2 2 2 2 1 22 1 y y dyy 1 1 2 2 yx. Then xy. If




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